Feb 4, 2015 · For the second derivative of #\sec(x)#, let's derive one more time the first derivative: again, ...

Sep 11, 2014 · Let us look at some details. y=secxtanx By Product Rule, y'=secxtanx cdot tanx+secx cdot sec^2x by factoring out sec x, =secx(tan^2x+sec^2x) by sec^2x=1+tan^2x, …

Sep 28, 2016 · What is the derivative of #y=sec^3(x)#? What is the derivative of #y=sec(x) tan(x)#? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x)

Aug 29, 2014 · The derivative of #y = tan(x)sec(x)# with respect to #x# is #(dy)/(dx) = sec^3(x) + sec(x)tan^2(x)#. To perform this differentiation, we will need to use the Product rule, which …

Sep 25, 2016 · #(secx-tanx)(sec x +tan x)# (The is the same bit of algebra we use to rationalize fractions involving #sqrta - b#. In this case applied to trigonometry.) #1/((sec x - tan x )) * ((sec …

Mar 8, 2018 · We have: # f(x)=secx # Using the limit definition of the derivative, we have: # f'(x) = lim_(h rarr 0) (f(x+h)-f(x))/h #

Dec 5, 2017 · What is the derivative of #y=sec^3(x)#? What is the derivative of #y=sec(x) tan(x)#? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x)

Mar 10, 2018 · The derivative is 2tanx. We can rewrite using trigonometry and the logarithm laws: y= ln(1/cos^2x) = ln(1) - ln(cos^2x) = 0 - ln((cosx)^2) = -2ln(cosx) Therefore by the chain rule y' …

Jul 27, 2014 · What is the derivative of #y=(1-sec(x))/tan(x)#? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer

Apr 12, 2015 · Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer